Acceleration on an Incline

In: Science

Submitted By sergiohpl
Words 874
Pages 4
Sergio Hernandez
Jose Roque
Paul Zuniga
October 7th, 2012
Laboratory Report: Acceleration on an Incline
Purpose:
0 Use a Motion Detector to measure the speed and acceleration of a cart rolling down an incline. 1 Determine the mathematical relationship between the angle of an incline and the acceleration of the cart. 2 Determine the value of free fall acceleration, g, by extrapolating the acceleration vs. sine of track angle graph. 3 Determine if an extrapolation of the acceleration vs. sine of track angle is valid.

Materials: * Computer * Vernier computer interface. * Logger Pro. * Vernier Motion Detector. * Dynamics cart. * Meter stick. * Ramp. * Books.

Procedure:
1. Connect the Motion Detector to the DIG/SONIC 1 channel of the interface.
2. Place a single book under one end of a 1 – 3 m long board or track so that it forms a small angle with the horizontal. Adjust the points of contact of the two ends of the incline, so that the distance, x, in Figure 1 is between 1 and 3 m.
3. Place the Motion Detector at the top of an incline. Place it so the cart will never be closer than 0.4 m.
4. Open the file “04 g On An Incline” from the Physics with Vernier folder.
5. Hold the cart on the incline about 0.5 m from the Motion Detector.
6. Click to begin collecting data; release the cart after the Motion Detector starts to click. Get your hand out of the Motion Detector path quickly. You may have to adjust the position and aim of the Motion Detector several times before you get it right. Adjust and repeat this step until you get a good run showing approximately constant slope on the velocity vs. time graph during the rolling of the ball.
7. Logger Pro can fit a straight line to a portion of your data. First indicate which portion is to be used by dragging across the graph to indicate the starting and…...

Similar Documents

Acceleration Due to Gravity

...Acceleration Due to Gravity Introduction In this lab you will measure the acceleration due to gravity near the earth’s surface with two experiments: first, by determining the time for a steel ball to fall a known vertical distance (free fall), and then second, by measuring the velocity of a cart at various points as it glides down a slightly inclined and nearly frictionless air track (slow fall). Equipment Part 1: Free-Fall • Free-fall apparatus (steel plate, drop mechanism) • Electronic Timer • Steel Ball Part 2: Slow-Fall • Air Track • Electronic Timer (may be different brand/model than in Part 1) • Gliding Car • Laser Photogate Background: Free Fall Acceleration Under the constant acceleration of gravity near the Earth’s surface, g, the vertical position, y, of a falling object is related to the time it has fallen by 1 y = y 0 + v 0 t " gt 2 2 where y0 and v0 are the initial position and velocity, respectively. The distance fallen after a time, t, has elapsed is: ! 1 y 0 " y = gt 2 " v 0 t 2 If you release the object from rest, v0 = 0, the equation simplifies to ! y0 " y = 1 2 gt 2 By varying the distance the ball drops and measuring the corresponding transit times, we can determine the acceleration of gravity from a best fit line to a linear graph of the experimental data. ! ! Procedure: Free-Fall Acceleration A diagram of the experimental apparatus is shown in Figure 1. When the ball loses contact with the release mechanism, the timer starts counting. It......

Words: 2143 - Pages: 9

Motion

...a horse that 
gallops a distance of 15 km in a time of 30 min is: Average speed = 15 km/30 min = 15 km/0.5 h = 30 km/h 5. Speed is the distance covered per unit of time. Acceleration is the rate in which an object changes its velocity. 6. If a car is moving at 90 km/h and it rounds a corner, also at 90 km/h, 
it does maintain a constant speed but not a constant velocity. The velocity never changed, only the direction it’s traveling. 7. Velocity is change in displacement, change in position over a period of time, while Acceleration is change in velocity over a time period. 8. The acceleration of a car that increases its velocity from 0, to 
100 km/h in 10s is 10km/h*s 9. The acceleration of a car that maintains a constant velocity of 
100 km/h for 10s is 0 km/h*s. Some of my classmates get this question wrong but the last question right because they fail to read the question. In the last question there was a change in velocity. However in this question there was no change in velocity. 10. We are most aware of moving in a vehicle when the vehicle is accelerating because gravity will push us back into the seat. 11. The relationship Galileo discover about a ball's acceleration and the steepness of an incline is the steeper the incline the faster the balls accelerate. Free fall acceleration occurs when the plane is vertical. 12. The velocity acquired by a freely falling object 5 s after being dropped from a rest position is 49m/s. at 6s it is 58.8m/s.......

Words: 495 - Pages: 2

Acceleration Incline

...P03: Acceleration on an Incline (Acceleration Sensor) |Concept |DataStudio |ScienceWorkshop (Mac) |ScienceWorkshop (Win) | |Linear motion |P03 Acceleration.ds |(See end of activity) |(See end of activity) | |Equipment Needed |Qty |Equipment Needed |Qty | |Acceleration Sensor (CI-6558) |1 |Dynamics Cart (inc. w/ Track) |1 | |Angle Indicator (inc. w/ Track) |1 |Meter stick |1 | |Base and Support Rod (ME-9355) |1 |1.2 m Track System (ME-9429A) |1 | What Do You Think? When a sled accelerates down a snow-covered hill, on what does its acceleration depend? You may want to consider the height of the hill, the slope of the hill and the mass of the sled. How does its acceleration depend on the variable(s) you selected? Take time to answer the ‘What Do You Think?’ question(s) in the Lab Report section. Background A cart on an incline will roll down the incline as it is pulled by gravity. The direction of the acceleration due to gravity is straight down as shown in the diagram. The component of the acceleration due......

Words: 1981 - Pages: 8

Homework

...Question 5 | | 1 / 1 point | In the figure shown, the coefficient of kinetic friction between the block and the incline is 0.40. What is the magnitude of the acceleration of the suspended block as it falls? Disregard any pulley mass or friction in the pulley. Question options: | 1)  | 3.4 m/s2 | | | 2)  | 3.7 m/s2 | | | 3)  | 4.2 m/s2 | | | 4)  | 3.9 m/s2 | | | 5)  | 5.4 m/s2 | | Question 34 | | 1 / 1 point | A 4.0-kg block slides down a 35 incline at a constant speed when a 16-N force is applied acting up and parallel to the incline. What is the coefficient of kinetic friction between the block and the surface of the incline? Question options: | 1)  | 0.20 | | | 2)  | 0.23 | | | 3)  | 0.26 | | | 4)  | 0.33 | | | 5)  | 0.41 | | Question 35 | | 1 / 1 point | A 1.0-kg block is pushed up a rough 22 inclined plane by a force of 7.0 N acting parallel to the incline. The acceleration of the block is 1.4 m/s2 up the incline. Determine the magnitude of the force of friction acting on the block. Question options: | 1)  | 1.9 N | | | 2)  | 2.2 N | | | 3)  | 1.3 N | | | 4)  | 1.6 N | | | 5)  | 3.3 N | | Question 40 | | 1 / 1 point | A 2.0-kg object has a velocity of 4.0i m/s at t = 0. A constant resultant force of (2.0i + 4.0j) N then acts on the object for 3.0 s. What is the magnitude of the object's velocity at the end of the 3.0-s interval? Question options: | 1)  | 9.2...

Words: 7510 - Pages: 31

Mechanics

...A 4.0-kg bucket of water is raised from a well by a rope. If the upward acceleration of the bucket is 5.0 m/s2, find the force exerted by the rope on the bucket. [59 N] 5. A block is pressed against a vertical wall by a force [pic], as the drawing shows. This force can either push the block upward at a constant velocity or allow it to slide downward at a constant velocity. The magnitude of the force is different in the two cases, while the directional angle ( is the same. Kinetic friction exists between the block and the wall, and the coefficient of kinetic friction is 0.250. The weight of the block is 39.0 N, and the directional angle for the force [pic] is ( = 30.0°. Determine the magnitude of when the block slides (a) up the wall and (b) down the wall. [(a) 52.6 N, (b) 39.4 N] 6. A 3.0 kg block is at rest on a horizontal floor. If you push horizontally on the 3.0 kg block with a force of 12.0 N, it just starts to move. (a) What is the coefficient of static friction? (b) A 7.0 kg block is stacked on top of the 3.0 kg block. What is the magnitude F of the force, acting horizontally on the 3.0 kg block that is required to make the two blocks start to move? [(a) 0.41, (b) 40 N] 7. The systems shown in figure below are in equilibrium. If the spring scales are calibrated in newtons, what do they read? Ignore the masses of the pulleys and strings and assume the pulleys and the incline in figure are frictionless. [49.1 N, 49.1 N, 98.1 N, 24.5 N] ...

Words: 937 - Pages: 4

A C Ool Nam a a S Dqi Dosjks

...upward acceleration of the bucket is 5.0 m/s2, find the force exerted by the rope on the bucket. [59 N] 5. A block is pressed against a vertical wall by a force [pic], as the drawing shows. This force can either push the block upward at a constant velocity or allow it to slide downward at a constant velocity. The magnitude of the force is different in the two cases, while the directional angle ( is the same. Kinetic friction exists between the block and the wall, and the coefficient of kinetic friction is 0.250. The weight of the block is 39.0 N, and the directional angle for the force [pic] is ( = 30.0°. Determine the magnitude of when the block slides (a) up the wall and (b) down the wall. [(a) 52.6 N, (b) 39.4 N] 6. A 3.0 kg block is at rest on a horizontal floor. If you push horizontally on the 3.0 kg block with a force of 12.0 N, it just starts to move. (a) What is the coefficient of static friction? (b) A 7.0 kg block is stacked on top of the 3.0 kg block. What is the magnitude F of the force, acting horizontally on the 3.0 kg block that is required to make the two blocks start to move? [(a) 0.41, (b) 40 N] 7. The systems shown in figure below are in equilibrium. If the spring scales are calibrated in newtons, what do they read? Ignore the masses of the pulleys and strings and assume the pulleys and the incline in figure are frictionless. [49.1 N, 49.1 N, 98.1 N, 24.5 N] 8. A 3.00 kg block starts from rest at the top of a 30.0° incline and......

Words: 938 - Pages: 4

Acceleration

...Acceleration 19. A steam catapult launches a jet aircraft from the aircraft carrier John C. Stennis, giving it a speed of 175 mi/h in 2.50 s. (a) Find the average acceleration of the plane. (b) Assuming that the acceleration is constant, find the distance the plane moves. 20. A car traveling in a straight line has a velocity of +5.0 m/s at some instant. After 4.0 s, its velocity is +8.0 m/s. What is the car’s average acceleration during the 4.0-s time interval? 26. A truck covers 40.0 m in 8.50 s while smoothly slowing down to a final speed of 2.80 m/s. (a) Find the truck’s original speed. (b) Find its acceleration. 27. A speedboat increases its speed uniformly from 20 m/s to 30 m/s in a distance of 200 m. Find (a) the magnitude of its acceleration and (b) the time it takes the boat to travel the 200-m distance. 28. Two cars are traveling along a straight line in the same direction, the lead car at 25.0 m/s and the other car at 30.0 m/s. At the moment the cars are 40.0 m apart, the lead driver applies the brakes, causing his car to have an acceleration of –2.00 m/s2. (a) How long does it take for the lead car to stop? (b) Assuming that the chasing car brakes at the same time as the lead car, what must be the chasing car’s minimum negative acceleration so as not to hit the lead car? (c) How long does it take for the chasing car to stop? 29. A Cessna aircraft has a lift-off speed of 120 km/h. (a) What minimum constant acceleration does the aircraft require if......

Words: 879 - Pages: 4

Acceleration vs Time

...Acceleration vs. Time * On the first graph, the man walks slowly to the house from the origin. On the Position-Time graph, the line is a positive consistent rise. This is because his position is going in a positive direction as well as the time is going in a consistent positive direction. On the Velocity-Time graph, the line is straight across at 2 m/s because the velocity does not change because of the consistent speed of the man walking to the house. Since the velocity is constant the acceleration is zero. On the Acceleration-Time graph, the line is flat and straight across at the 0 m/s line because the man does not accelerate. He just walks at a consistent pace to the house. This is called constant speed because there is no variation in his speed. * On the second example, the man is sleeping then wakes up and runs toward the house constantly speeding up as he goes. On the Position-Time graph, there is a positive upward curved line. This is because both are moving in a positive direction but because he is running, the position is rising faster than the time. This upward curve indicates an increase in velocity. On the Velocity-time graph, the line is a straight consistent rise. This is caused because the man is running so the velocity is rising throughout the graph, as is the position. A positive slope indicates a changing velocity which is a positive acceleration. On the Acceleration-Time graph, the line constantly rising because the man is running, constantly......

Words: 550 - Pages: 3

Kinematics - Velocity and Acceleration

...Lab #4: Kinematics - Velocity and Acceleration Introduction: The purpose of this lab is to discover and understand the relationships between position, velocity, and acceleration. Additionally, constant/uniform acceleration due to the force of gravity will be examined to find possible mathematical relationships to position and velocity. Velocity and acceleration are changes in position and velocity, respectively, with regards to time. This change can be shown mathematically in calculus derivatives: EQ 1. EQ 2. As dt decreases in value, the instantaneous velocity and acceleration can also be found. Furthermore, if constant acceleration is established, two basic relations between distance, velocity, and the constant acceleration can be found: EQ 3. EQ 4. In any environment near Earth, the acceleration in the vertical direction is constant at a value of g=9.8m/s2 towards the center of Earth or often written as g=-9.8m/s2. In such an environment there is no natural acceleration in the horizontal direction, thus the horizontal motion is analyzed independently of the vertical motion. Thus it can be established that the general form of a position curve for a projectile would follow an inverse parabola shape and the maximum height occurs when vertical velocity is zero. By calculus derivation, it can also be found that the velocity graph would display a linear line with a negative slope. Procedure: This lab consists of two separate but related......

Words: 1974 - Pages: 8

2nd Law

...force ¢ along a rough steel plate, as shown below for two cases. The magnitude of the applied force ¢ is the same for both cases. The normal force in (ii), as compared with the normal force in (i) is:| A)|the same| B)|greater| C)|less| D)|less for some angles of the incline and greater for others| E)|less or greater, depending on the magnitude of the applied force ¢.| 4.|A 6-kg object is moving south. A net force of 12 N north on it result in the object having an acceleration of: | A)|2 m/s2, north | B)|2 m/s2, south | C)|6 m/s2, north | D)|18 m/s2, north | E)|18 m/s2, south | 5.|A 9000 N automobile is pushed along a level road by four students who apply a total forward force of 500 N. Neglecting friction, the acceleration of the automobile is: | A)|0.055m/s2| B)|0.54 m/s2| C)|1.8 m/s2| D)| 9.8 m/s2| E)|18 m/s2| 6.|A 25-kg crate is pushed across a frictionless horizontal floor with a force of 20 N, directed 20° below the horizontal. The acceleration of the crate is: | A)|0.27 m/s2| B)|0.75 m/s2| C)|0.80 m/s2| D)|170 m/s2| E)|470 m/s2| 7.|Two forces are applied to a 5.0-kg crate; one is 6.0 N to the north and the other is 8.0 N to the west. The magnitude of the acceleration of the crate is: | A)|0.50 m/s2| B)|2.0 m/s2| C)|2.8 m/s2| D)|10 m/s2| E)|50 m/s2| 8.|A 1000-kg elevator is rising and its speed is increasing at 3 m/s2. The tension in the elevator cable is: | A)|6800 N | B)|1000 N | C)|3000 N | D)|9800 N | E)|12800 N......

Words: 2576 - Pages: 11

Efds

...Measuring motion We want to measure the motion of a ball that rolls down on an inclined plane and see whether this matches what we would expect. We will roll a ball down a tilted aluminum plate where gravity will accelerate the ball. It then rolls along a level surface (Plexiglas) where it should roll with approximately constant velocity as long as friction can be neglected. • Set up the experiment. Start by placing the large wooden board onto the table, and use the adjustment screws and the level to ensure the plane is level. Place the Plexiglas strip onto the wood and use a steel ball to check again that it is indeed level. • Place the ramp onto the metal inclines and use the magnets to secure it. Make sure the ramp touches the horizontal surface, but does not flex at the edge of the inclines. • One challenge is to launch the ball without giving it a kick. This is possible with a magnetic launch mechanism you can put together using an electromagnet, a power source and a switch. Clamp the electromagnet to the metal surface approximately 20 cm up the ramp. When the circuit is closed, the current through the electromagnet will generate a magnetic field that will hold the ball bearing at the electromagnet on the ramp. To release the ball bearing, simply open the switch to break the current. Find the minimum voltage needed to hold the ball. Set it slightly higher. Caution: If the voltage is too high, the electromagnet will heat up and might get......

Words: 2038 - Pages: 9

Disbursement Acceleration Program

...THE DISBURSEMENT ACCELERATION PROGRAM MELISSA R. MARTIN MPAD 610 –PUBLIC MANAGEMENT AND SOCIAL CHANGE CONTENT * What is DAP? * Why was DAP introduced? * How did the DAP work? * How did DAP benefit the economy? * How did DAP support the budget reform agenda? * DAP Timeline * Constitutional and Legal Bases of DAP * SC Ruling on DAP * Why did the Aquino Administration terminate DAP? * SC modifies ruling on DAP What is DAP? The Disbursement Acceleration Program (DAP) is a spending reform measure to speed up public expenditure and catalyze economic growth. Why was DAP introduced? * Need to Clean House: Curb Corruption and Leakages * Freeing up operational bottlenecks * Inefficient implementation * Poor planning * Slow procurement * By the third quarter of 2011, it became clear that if we wanted public spending to accelerate enough for economic growth, we had to use idle funds. (Sec. Florencio Abad, DBM ) * The Aquino Administration therefore launched the DAP in 2011 KEY REFORMS (the DAP as Package of Reform Intervention) * Zero-based budgeting Implementation of zero-based budgeting to weed out inefficient, ineffective and leakage-ridden programs and projects * Early enactment of the budget Early preparation, submission and enactment of the annual National Budget including the adoption of the Online Submission of Budget Proposal * Disaggregation of lump sum......

Words: 2422 - Pages: 10

Physics Projectile

...inclined plane: Measuring motion We want to measure the motion of a ball that rolls down on an inclined plane and see whether this matches what we would expect. We will roll a ball down a tilted aluminum plate where gravity will accelerate the ball. It then rolls along a level surface (Plexiglas) where it should roll with approximately constant velocity as long as friction can be neglected. • Set up the experiment. Start by placing the large wooden board onto the table, and use the adjustment screws and the level to ensure the plane is level. Place the Plexiglas strip onto the wood and use a steel ball to check again that it is indeed level. • Place the ramp onto the metal inclines and use the magnets to secure it. Make sure the ramp touches the horizontal surface, but does not flex at the edge of the inclines. • One challenge is to launch the ball without giving it a kick. This is possible with a magnetic launch mechanism you can put together using an electromagnet, a power source and a switch. Clamp the electromagnet to the metal surface approximately 20 cm up the ramp. When the circuit is closed, the current through the electromagnet will generate a magnetic field that will hold the ball bearing at the electromagnet on the ramp. To release the ball bearing, simply open the switch to break the current. Find the minimum voltage needed to hold the ball. Set it slightly higher. Caution: If the voltage is too high, the electromagnet will heat up and might get destroyed.......

Words: 2047 - Pages: 9

Science Exp>

...Experiment #6-FREE FALL FALLING BODIES OBJECTIVES: 1.To describe how the velocity and acceleration of an object change over time when falling under the influence of gravity and to explain why such changes are observed. 2. To determine gravitational acceleration by studying the velocity of a falling object as a function of time. INTRODUCTION: Everything on Earth is under the influence of it’s gravitational field keeping us from jumping of respected measure high.Along with this things that are on Earth,there are objects that are soon to be on Earth’s surface,falling objects have certain interactions with Earth’s gravity.Air resistance is a factor of free-falling objects.Since Earth has an atmosphere,the speed of which objects fall at are not constant. While you are falling, you will probably feel as if you are floating—or not even moving at all. Falling is relational—if there is nothing to fall toward, you may not even be aware that you’re falling. If there is no ground, gravity might be low and you’ll feel weightless. Objects will stay suspended if you let go of them. Whole societies around you may be falling just as you are. And it may actually feel like perfect stasis—as if history and time have ended and you can’t even remember that time ever moved forward. A free falling object is an object that is falling under the sole influence of gravity. Any object that is being acted upon only by the force of gravity is said to be in a state of free fall.......

Words: 9435 - Pages: 38

Centripetal Acceleration Lab

...Centripetal Acceleration Lab Purpose: To understand and verify the relationship of Centripetal Force, where m is mass, v is velocity and r is radius. Procedure: Part 1: Set up apparatus, which consists of a rotor mechanism containing a mass m attached to a spring. Tape on a piece of cardboard vertically onto one end of the rotor to trigger the photogate timer. Start the rotor and gradually increase speed until the metal pointer just flips up. Record the time (up). And then gradually decrease until the metal pointer just flips down. Record the time (down). Calculate the force on the rotating mass m. Part 2: Rotate rotor from Part 1 so that mass m hangs straight down. Attach a short loop of fishing line at the bottom of the mass. Add weight (mass) onto loop and keep adding weight until the metal pointer just flips up. Record the mass (up). Then little by little, remove the weights until the metal pointer just flips down. Record the mass (down). Calculate Force=mg. Data/Results: The data and sample calculations are attached below. The typical relative uncertainty for Fc was 16%, while the typical relative uncertainty for Fg was 2%. Thus Fg is a more precise measurement than Fc. Both parts gave the similar Newton answers (about 21-22N). Some error in this lab may have been caused by air resistance/friction, slowing down mass and increasing period. Another error can be caused by time measurement/calibration, which can be reduced by timing a number of rev and......

Words: 305 - Pages: 2